Railways R.R.C. (Jabalpur) Solved Paper Held on 1st Shift 30-11-2014

  • question_answer In order of pass in an examination, a student is required to get 280 marks out of the aggregate marks. Nema got 264 marks and was declared fail by 2%. What is the minimum passing percentage of the examination?

    A) 35                                

    B) 30

    C) 40                                

    D) 44

    Correct Answer: A

    Solution :

    Let the aggregate marks =x. Then. \[\frac{(280-264)}{x}\times 100=2\]                           \[x=\frac{16\times 100}{2}\]                            \[x=800\] Now, the minimum passing percentage of the examination    \[=\frac{280}{800}\times 100%\]                          \[=35%\]     


You need to login to perform this action.
You will be redirected in 3 sec spinner