A) ±10
B) ±12
C) (c)\[-10\]
D) None of these
Correct Answer: B
Solution :
\[\sqrt{{{(0-x)}^{2}}+{{(-5-0)}^{2}}}=13\] \[{{x}^{2}}+25=169\] \[{{x}^{2}}=169-25\] \[=144\] \[x=\pm \,\,12\]You need to login to perform this action.
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