A) 10th
B) 9th
C) 8th
D) 11th
Correct Answer: B
Solution :
\[1280=5\times {{(2)}^{n-1}}\] \[256={{2}^{n-1}}\] \[{{2}^{8}}={{2}^{n-1}}\] \[\therefore \] \[n-1=8\] \[\therefore \] \[n=9th\]You need to login to perform this action.
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