A) \[3\sqrt{3}\]
B) \[8\sqrt{3}\]
C) \[14+8\sqrt{3}\]
D) 14
Correct Answer: D
Solution :
\[x+\frac{1}{x}=7-4\sqrt{3}+\frac{1}{7-4\sqrt{3}}\] \[=7-4\sqrt{3}+\frac{7+4\sqrt{3}}{49-48}\] \[=7-4\sqrt{3}+7+4\sqrt{3}=14\]You need to login to perform this action.
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