A) 18
B) 12
C) 14
D) 15
Correct Answer: D
Solution :
Suppose three consecutive integers are x, x+1, and x +1. Then, \[x(x+1)(x+2)=120\] \[x({{x}^{2}}+3x+2)=120\] \[{{x}^{3}}+3{{x}^{2}}+2x-120=0\] On solving \[x=4\] Now, sum of the integers\[=x+x+1+x+2\] \[=3x+3\] \[=3\times 4+3=15\]You need to login to perform this action.
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