A) \[\frac{160}{81}\]
B) \[\frac{160}{3}\]
C) \[\frac{2}{81}\]
D) \[\frac{2}{3}\]
Correct Answer: D
Solution :
The H.C.F. of 2, 8, 10 and 32=2 and the H.C.F. of 3, 9, 27 and 81 = 3 then, H.C.F. =\[\frac{2}{3}\]You need to login to perform this action.
You will be redirected in
3 sec