Answer:
Given, \[\Delta \,ABC\sim \Delta \,DEF,\] Perimeter of \[\Delta \,ABC=50\,cm\] Perimeter \[\Delta \,DEF=70\,\,cm\] One side of \[\Delta \,ABC=20\text{ }cm\] Let \[AB=20\text{ }cm\] \[\Delta \,ABC\sim \Delta \,DEF\] [Given] \[\therefore \frac{\text{Peri}\,(\Delta \,ABC)}{\text{Peri}\,(\Delta \,DEF)}=\frac{AB}{DE}\] \[\frac{50}{70}=\frac{20}{DE}\] \[\Rightarrow 5DE=140\] \[DE=28\,\,m\] The corresponding side of \[\Delta \,DEF=28\text{ }cm\].
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