10th Class Mathematics Solved Paper - Mathematics-2014 Term-I

  • question_answer
    Cost of living Index for some period is given in the following frequency distribution:
    Index 1500 ? 1600 1600 ? 1700 1700 ? 1800 1800 ? 1900 1900 ? 2000 2000 ? 2100 2100 ? 2200
    No. of weeks 3 11 12 7 9 8 2
    Find the mode and median for above data.

    Answer:

    Index Number of weeks \[({{f}_{i}})\] \[c{{f}_{i}}\]
    1500 ? 1600 3 3
    1600 ? 1700      11  \[{{f}_{0}}\] 14
    1700 ? 1800     12  \[{{f}_{1}}\] 26
    1800 ? 1900       7   \[{{f}_{2}}\] 33
    1900 ? 2000 9 42
    2000 ? 2100 8 50
    2100 ? 2200 2 52
    \[\sum{{{f}_{i}}=52}\]
                                        \[n=52\]
                                        \[\frac{n}{2}=\frac{52}{2}=26\]
    \[\therefore \] Median class is 1700 ? 1800
    Median \[=l+\frac{\frac{n}{2}-cf}{f}\times h\]
                \[=1700+\frac{26-14}{12}\times 100\]
    \[\frac{n}{2}=1700+\left( \frac{12}{12}\times 100 \right)=1800\]
    Maximum frequency is 12
    \[\therefore \] Modal class is 1700 ? 1800
    Mode \[=l+\frac{{{f}_{1}}-{{f}_{0}}}{2{{f}_{1}}-{{f}_{0}}-{{f}_{2}}}\times h\]
                \[=1700+\frac{12-11}{24-11-7}\times 100\]
                \[=1700+\frac{1}{6}\times 100\]
                \[=1700+16.67\]
                \[=1716.67\]


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