Answer:
Let \[x=6.\overline{12}\] ?(i) \[\Rightarrow 100x=6.\overline{12}\] ?(ii) Subtracting eq. (i) from (ii), we get \[99x=606\] \[x=\frac{606}{99}=\frac{202}{33}\] \[\therefore \] Denominator \[=33\] Prime factorisation \[=3\times 11\]
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