Answer:
Steps of construction: (i) Draw a line segment \[AB=6\text{ }cm\]. (ii) Construct \[\angle ABP=60{}^\circ \] and \[\angle QAB=30{}^\circ \] (iii) Join AC and BC such that C is the intersection point of BP and AQ. Thus, \[\Delta \,ABC\] is the required triangle. (iv) Extend AB to B', such that \[AB'=8\text{ }cm\]. (v) Draw \[B'C'\parallel BC\] cutting AC produced at C?. Then, \[\Delta \,AB'C'\] is the required triangle similar to \[\Delta \,ABC\].
You need to login to perform this action.
You will be redirected in
3 sec