Answer:
Consider the given equation \[2{{x}^{2}}+6\sqrt{3}x-60=0\] \[\Rightarrow {{x}^{2}}+3\sqrt{3}x-30=0\] ?(i) Comparing equation (i) by \[a{{x}^{2}}+bx+c=0\] We get \[a=1,b=3\sqrt{3},c=-30\]. By quadratic formula \[x=\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\] \[x=\frac{-3\sqrt{3}\pm \sqrt{27+120}}{2}\] \[x=\frac{-3\sqrt{3}\pm \sqrt{147}}{2}\] Hence value for \[x=\frac{-3\sqrt{3}\pm \sqrt{147}}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec