Answer:
\[17\times 5\times 11\times 3\times 2+2\times 11=17\times 5\times 3\times 22+22\] ...(i) \[=22\,(17\times 5\times 3+1)\] \[=22\text{ (}255+1)=2\times 11\times 256\] Equation (i) is divisible by 2, 11 and 256, which means it has more than 2 prime factors. \[\therefore \,\,(17\times 5\times 11\times 3\times 2+2\times 11)\] is a composite number.
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