Answer:
Given, diameter and height of cylindrical well are 4 m and 21 m respectively. Now, the earth has been taken out to spread evenly all around. Then, volume of earth dug out \[=\frac{22}{7}\times \frac{3}{4}\times \frac{1}{3}\times 21\]\[=264\,{{m}^{3}}\] And the volume of embankment of width 3 m which forms a shape of circular ring \[=\pi ({{(5)}^{2}}-{{(2)}^{2}})\times h\] \[=\frac{22}{7}(25-4)\times h=66\,h\,{{m}^{3}}\] [\[\because \] Outer radius \[=2+3=5\,cm\]] \[\because \] Volume of earth dug out = Volume of embankment \[\therefore 264=66h\] \[\Rightarrow h=\frac{264}{66}=4\,m\] Hence, the height of the embankment is 4 m.
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