Answer:
We have, \[k+9,\text{ }2k-1\] and \[2k+7\] as consecutive terms of an A.P Then, \[2\,(2k-1)=k+9+2k+7\] [if a, b and c are in A.P. then \[2b=a+c\]] \[4k-2=3k+16\] \[k=18\]
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