Answer:
Radius of the base of cylinder \[(r)=2.8\,m\] Radius of the base of the cone \[(r)=2.8\,m\] Height of the cylinder \[(h)=3.5\,m\] Height of the cone \[(H)=2.1\,m\]. Slant height of conical part \[(l)=\sqrt{{{r}^{2}}+{{H}^{2}}}\] \[=\sqrt{{{(2.8)}^{2}}+{{(2.1)}^{2}}}\] \[=\sqrt{7.84+4.41}\] \[=\sqrt{12.25}\] \[=3.5\,m\] Area of canvas used to make tent = CSA of cylinder + CSA of cone \[=2\times \pi \times 2.8\times 3.5+\pi \times 2.8\times 3.5\] \[=61.6+30.8\] \[=92.4\text{ }{{m}^{2}}\] Cost of 1500 tents at Rs. 120 per sq. m \[=1500\times 120\times 92.4\] \[=Rs.\,\,16,632,000\] Share of each school to set up the tents \[=\frac{16632000}{50}\] \[=Rs.\,332,640\] Value ? Be kind and help others in need.
You need to login to perform this action.
You will be redirected in
3 sec