Answer:
Steps of construction: (i) Draw a circle with O as centre and radius \[4\text{ }cm\]. (ii) Draw any diameter AOB of this circle. (iii) Construct \[\angle BOC=60{}^\circ \] such that radius OC meets the circle at C. (iv) Draw \[AM\bot AB\] and \[CN\bot OC\]. Let AM and CN intersect each other at P Then, PA and PC are the required tangents to the given circle and inclined at an angle of \[60{}^\circ \] to each other.
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