• # question_answer A number x is selected at random from the numbers 1, 2, 3 and 4. Another number y is selected at random from the numbers 1, 4, 9 and 16. Find the probability that product of x and y is less than 16.

 Let x be 1, 2, 3 or 4 and y be 1, 4, 9 or 16. Now, $xy=\{1,4,9,16,2,8,18,32,3,12,27,48,4,16,36,64\}$ Total number of possible outcomes $=16$ Number of outcomes where product is less than $16=8$ i.e., $\{1,4,9,2,8,3,12,4\}$ $\therefore$ Required probability $=\frac{8}{16}=\frac{1}{2}$