Answer:
Given, a tangent AB at point P of the circle with centre O. To prove: . Construction: Join OQ where Q is a point (other than P) on AB. Proof: Since Q is a point on the tangent AB (other than P). Q lies outside the circle. Let OQ intersect the circle at R. . But . (Radii of the circle) . Thus, OP is the shortest distance than any other line segment joining O to any point of AB. But, we know that the shortest distance between a point and a line is the perpendicular distance Hence Proved.
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