Answer:
Let x be 1, 4, 9, 16 and y be 1, 2, 3, 4. Now, \[xy=\{1,2,3,4,4,8,12,16,9,18,27,36,16,32,48,64\}\] Total number of possible outcomes \[=16\] Number of outcomes where product is more than \[16=6\] i.e., \[\{18,27,36,32,48,64\}\] \[\therefore \] Required probability \[=\frac{6}{16}=\frac{3}{8}\]
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