Answer:
Given, \[\frac{AB}{BC}=\frac{\sqrt{3}}{1}\] In \[\Delta \,ABC\] \[\tan \,\,\theta =\frac{AB}{BC}=\frac{\sqrt{3}}{1}\] \[\Rightarrow \] \[=60{}^\circ \] Hence, the angle of elevation is \[60{}^\circ \].
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