question_answer

Draw a right triangle in which the sides (other than the hypotenuse) are of lengths \[4\text{ }cm\] and \[3\text{ }cm\]. Now construct another triangle whose sides are \[\frac{3}{5}\] times the corresponding sides of the given triangle.

Answer:

Steps of construction-

(i) Draw \[AB=4\text{ }cm\]

(ii) Draw \[AC\bot AB\] of \[3\text{ }cm\]

(iii) Join \[BC\]

(iv) Draw an acute angle at A with 5 equidistant marks

(v) Join \[{{A}_{5}}B\]

(vi) Draw \[{{A}_{3}}B'\parallel {{A}_{5}}B\].

(vii) Draw \[B'C'\parallel BC\].

(viii) \[AB'C'\] is required triangle.