Answer:
Let aeroplane is at A, 300 m high from a river. C and D are opposite banks of river. In right \[\Delta \,ABC\], \[\frac{BC}{AB}=\cot \,\,60{}^\circ \] \[\Rightarrow \] \[\frac{x}{300}=\frac{1}{\sqrt{3}}\Rightarrow x=\frac{300}{\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}\] \[=100\sqrt{3}m\] \[=100\times 1.732=173.2\,m\] In right \[\Delta \,ABD\], \[\Rightarrow \] \[\frac{BD}{AB}=\cot \,\,45{}^\circ \] \[\Rightarrow \] \[\frac{y}{300}=1\,\Rightarrow y=300\] Width if river \[=x+y\] \[=173.2+300\] \[=473.2m\]
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