Answer:
Given, no. of white balls \[=15\] Let no. of black balls \[=x\] \[\therefore \] Total balls \[=15+x\] According to the question, P (Black ball) \[=3\times P\] (White ball) \[\Rightarrow \] \[\frac{x}{(15+x)}=3\times \frac{15}{(15+x)}\] \[\Rightarrow \] \[x=45\] \[\therefore \] No. of black balls in bag \[=45\]
You need to login to perform this action.
You will be redirected in
3 sec