Answer:
Let B can finish a work in x days so, A can finish work in \[(x-6)\] days Together they finish work in 4 days Now, \[\frac{1}{x}+\frac{1}{x-6}=\frac{1}{4}\] \[\frac{x-6+x}{(x)(x-6)}=\frac{1}{4}\] \[4(2x-6)={{x}^{2}}-6x\] \[8x-24={{x}^{2}}-6x\] \[{{x}^{2}}-14x+24=0\] \[{{x}^{2}}-12x-2x+24=0\] \[x(x-12)-2(x-12)=0\] \[(x-12)(x-2)=0\] Either \[x-12=0\] or \[x-2=0\] \[x=12\]or \[x=2\], (Rejected) B can finish work in 12 days A can finish work in 6 days
You need to login to perform this action.
You will be redirected in
3 sec