10th Class Mathematics Solved Paper - Mathematics 2017 Outside Delhi Set-III

  • question_answer Solve for x: \[\frac{x-1}{2x+1}+\frac{2x+1}{x-1}=2\], where \[x\ne -\frac{1}{2},1\]

    Answer:

    \[\frac{{{x}^{2}}+1-2x+4{{x}^{2}}+1+4x}{2{{x}^{2}}-x-1}=\frac{2}{1}\]
                \[5{{x}^{2}}+2x+2=2(2{{x}^{2}}-x-1)\]
                \[5{{x}^{2}}+2x+2=4{{x}^{2}}-2x-2\]
                \[{{x}^{2}}+4x+4=0\]
                     \[{{(x+2)}^{2}}=0\]
    Either \[x+2=0\] or \[x+2=0\]
                   \[x=-2,-2\]


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