Answer:
\[\frac{{{x}^{2}}+1-2x+4{{x}^{2}}+1+4x}{2{{x}^{2}}-x-1}=\frac{2}{1}\] \[5{{x}^{2}}+2x+2=2(2{{x}^{2}}-x-1)\] \[5{{x}^{2}}+2x+2=4{{x}^{2}}-2x-2\] \[{{x}^{2}}+4x+4=0\] \[{{(x+2)}^{2}}=0\] Either \[x+2=0\] or \[x+2=0\] \[x=-2,-2\]
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