Two different dice are tossed together. Find the probability: |
(i) of getting a doublet |
(ii) of getting a sum 10, of the numbers on the two dice. |
Answer:
Total outcomes on tossing two different dice = 36 (i) A: getting a doublet \[A=\{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)\}\] \[\therefore \] Number of favourable outcomes of \[A=6\] \[\therefore \] \[P(A)=\frac{Favourable\,\,outcomes}{Total\,\,outcomes}\] \[=\frac{6}{36}=\frac{1}{6}\] (ii) B: getting a sum 10. \[B=\{(4,6),(5,5),(6,4)\}\] \[\therefore \] Number of favourable outcomes of B = 3 \[\therefore \] \[P(B)=\frac{Favourable\,\,outcomes}{Total\,\,outcomes}\] \[\therefore \] \[=\frac{3}{36}=\frac{1}{12}\]
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