• # question_answer If $x=3$is one root of the quadratic equation ${{x}^{2}}-2kx-6=0$, then find the value of k.

 Given quadratic equation is, ${{x}^{2}}-2kx-6=0$ $x=3$ is a root of above equation, then ${{(3)}^{2}}-2k(3)-6=0$ $9-6k-6=0$ $3-6k=0$ $3=6k$ $\therefore$      $k=\frac{3}{6}=\frac{1}{2}$ $k=\frac{1}{2}$