Answer:
Given, \[\Delta \text{ }ABC\tilde{\ }\Delta \text{ }PQR\] And \[\frac{AB}{PQ}=\frac{1}{3}\] Now \[\frac{ar(\Delta \,ABC)}{ar(\Delta \,PQR)}=\frac{A{{B}^{2}}}{P{{Q}^{2}}}\] \[={{\left( \frac{1}{3} \right)}^{2}}=\frac{1}{9}\]
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