In fig. 1, ABCD is a rectangle. Find the values of x and y. |
Answer:
Given, ABCD is a rectangle. \[\therefore \] \[AB=CD\] \[\Rightarrow \] \[30=x+y\] Or \[x+y=30\] Similarly, \[AD=BC\] ?(i) \[\Rightarrow \] \[14=x-y\] Or \[x-y=14\] On adding eq. (i) and (ii), we get ?(ii) \[2x=44\] \[\Rightarrow \] \[x=22\] Putting the value of x in eq. (i), we get \[22+y=30\] \[\Rightarrow \] \[y=30-22\] \[\Rightarrow \] \[y=\text{ }8\] So, \[x=22,\text{ }y=8\].
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