Answer:
Given, \[I=5A,\] No. of lamps = n, and Power, P = 40 W Power of 1 bulb = 40 W Power of n bulbs = 40n watt We know, \[P=V\times I\] \[40n=220\times 5\] \[\Rightarrow \] \[n=\frac{220\times 5}{40}=\frac{55}{2}=27.5\] \[\therefore \] No. of lamps = 27
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