Answer:
Given, \[u=-15\,cm,\,f=20\,cm\]
\[\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\]
\[\frac{1}{20}=\frac{1}{v}+\frac{1}{15}\]
\[\frac{1}{v}=\frac{1}{20}-\frac{1}{15}\]
\[v=-60\,cm\]
Four characteristics of the image formed by the lens are:
(i) Virtual, (ii) Erect, (iii) At a distance of 60 cm on the same side of the lens as the object, (iv) Enlarged image.
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