A) 714.43 sq. metre
B) 772.14 sq. metre
C) 783.86 sq. metre
D) 942.85 sq. metre
Correct Answer: D
Solution :
Curved surface area of cylindrical part \[=2\pi rh\] \[=2\times \frac{22}{7}\times 10\times 5\] \[=\frac{2200}{7}\]sq. metre Curved surface area of conical part \[=\pi rt\] \[=\frac{22}{7}\times 10\times 15\] \[=\frac{3300}{7}\]sq. metre Total curved surface area \[=\left( \frac{2200}{7}+\frac{3300}{7} \right)\,\text{sq}\text{.}\,\text{metre}\] \[\therefore \]Area of required canvas \[=\left( \frac{5500}{7}\times \frac{120}{100} \right)\,\text{sq}\text{.}\,\text{metre}\] = 942.85 sq. metreYou need to login to perform this action.
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