A) \[64\pi \,sq\,.cm.\]
B) \[25\pi \,sq\,.cm.\]
C) \[36\pi \,sq\,.cm.\]
D) \[49\pi \,sq\,.cm.\]
Correct Answer: B
Solution :
The sum of opposite angles of a cycle quadrilateral is\[{{180}^{o}}\]. \[\therefore \]\[\angle A=\angle B=\angle C=\angle D=90{}^\circ \] \[\therefore \] ABCD is a rectangle. AB = 8 cm., BC = 6 cm. \[\therefore \]\[AC=\sqrt{A{{B}^{2}}+B{{C}^{2}}}\] \[=\sqrt{{{8}^{2}}+{{6}^{2}}}=\sqrt{64+36}=\sqrt{100}\] = 10 cm. \[\therefore \]Radius of circle = 5 cm. \[\therefore \]Area of circle \[=\pi {{r}^{2}}\] \[=\pi \times 5\times 5=225\,sq.\,cm.\]You need to login to perform this action.
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