A) 1
B) 2
C) 0
D) 4
Correct Answer: A
Solution :
Let the number be\[x.\]According to the question. \[x+\frac{1}{x}=2\] \[\Rightarrow \]\[{{x}^{2}}+1=2x\] \[\Rightarrow \]\[{{x}^{2}}-2x+1=0\] \[\Rightarrow \]\[{{(x-1)}^{2}}=0\] \[\Rightarrow \]\[x-1=0\] \[\Rightarrow \]\[x=1\]You need to login to perform this action.
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