SSC SSC CHSL TIER-I Solved Paper Held on 08.01.2017

  • question_answer
    Chord AB of a circle when ex- tended meets the tangent to the circle at point P. PT is the tangent touching the circle at point T. If lengths of FT and PB are 6 cm. and 4 cm. respectively, what is the length of PA?

    A)  12 cm.

    B)  18 cm.

    C)  27 cm.

    D)  9 cm.

    Correct Answer: D

    Solution :

      \[PB.PA=P{{T}^{2}}\] \[\Rightarrow \]\[4\times PA=P{{T}^{2}}\] \[\Rightarrow \]\[PA=\frac{6\times 6}{4}=9\,cm.\]


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