A) \[4.3\times {{10}^{-2}}N{{m}^{-1}}\]
B) \[5.6\times {{10}^{-2}}N{{m}^{-1}}\]
C) \[6.3\times {{10}^{-2}}N{{m}^{-1}}\]
D) \[7.3\times {{10}^{-2}}N{{m}^{-1}}\]
Correct Answer: C
Solution :
Given that Density of liquid \[(\text{D})=800\text{ }kg{{m}^{-3}}\] Height of liquid \[\left( h \right)\text{ }=\text{ }4\text{ }cm\text{ }=\text{ }0.04\text{ }m\] Acceleration due to gravity \[(g)=9.8m/{{s}^{2}}\] Diameter of tube \[\left( d \right)\text{ }=\text{ }0.8\text{ }mm\] Radius of tube \[(r)=0.4\text{ }mm=4\times {{10}^{-4}}m\] Surface tension \[\left( T \right)\text{ }=\text{ }?\] By using \[T=\frac{rhDg}{2}\] \[=\frac{(4\times {{10}^{-4}})\times (.04)\times 800\times 9.8}{2}\] \[=4\times {{10}^{-4}}\times .04\times 400\times 9.8\] \[=4\times 4\times 4\times 98\times {{10}^{-5}}\] Hence, \[T=6.272\times {{10}^{-2}}=6.3\times {{10}^{-2}}N{{m}^{-1}}\]You need to login to perform this action.
You will be redirected in
3 sec