A) \[\frac{MR}{2T}\]
B) \[\frac{2T}{MR}\]
C) \[\frac{T}{MR}\]
D) \[\frac{MR}{T}\]
Correct Answer: B
Solution :
The torque exerted on the disc is given by \[\tau =TR\] ...(1) Also \[\tau =I\alpha \] ?(2) From eqs. (1) and (2), we get \[I\alpha =TR\] \[\alpha =\frac{TR}{I}\] Or \[\alpha =\frac{2TR}{M{{R}^{2}}}\] Or \[\alpha =\frac{2T}{mR}\]You need to login to perform this action.
You will be redirected in
3 sec