A) 1.21
B) 1.33
C) 2.80
D) 1.40
Correct Answer: D
Solution :
The specific heat of diatomic gas at constant pressure \[{{C}_{P}}=\frac{7}{2}R\] ...(1) and specific heat of diatomic gases at constant volume \[{{C}_{\upsilon }}=\frac{5}{12}R\] ...(2) Hence, from quation (1) and (2) we get \[\frac{{{C}_{p}}}{{{C}_{\upsilon }}}=\frac{\frac{7}{2}R}{\frac{5}{2}R}=\frac{7}{5}=1.4\]You need to login to perform this action.
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