A) \[6.17\times {{10}^{-21}}J\]
B) \[61.7\times {{10}^{-23}}J\]
C) \[6.17\times {{10}^{-20}}J\]
D) \[6.17\times {{10}^{-20}}J\]
Correct Answer: A
Solution :
The average kinetic energy per molecule \[=\frac{3RT}{2n}\] Here, \[T=25+273=298K\] \[R=8.314\] \[=\frac{3\times 8.314\times 298}{2\times (6.02\times {{10}^{23}})}\] \[=6.17\times {{10}^{-21}}J\]You need to login to perform this action.
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