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Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    In gases of diatomic molecules, the ratio of two specific heats of gases \[\frac{{{C}_{p}}}{{{C}_{\upsilon }}}\] is :

    A)  1.21  

    B)  1.33  

    C)  2.80  

    D)  1.40

    Correct Answer: D

    Solution :

     The specific heat of diatomic gas at constant pressure \[{{C}_{P}}=\frac{7}{2}R\]                  ...(1) and specific heat of diatomic gases at constant volume \[{{C}_{\upsilon }}=\frac{5}{12}R\]               ...(2) Hence, from quation (1) and (2) we get \[\frac{{{C}_{p}}}{{{C}_{\upsilon }}}=\frac{\frac{7}{2}R}{\frac{5}{2}R}=\frac{7}{5}=1.4\]


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