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Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    A black body at a temperature of 900 K emits energy at a rate, which is proportional to:

    A)  \[{{(900)}^{3}}\]             

    B)  \[{{(900)}^{4}}\]

    C)  (900)              

    D)  \[{{(900)}^{2}}\]

    Correct Answer: B

    Solution :

     Temperature of a black body T = 900 K According to Stefans law total energy emitted energy by the black body is \[E={{T}^{4}}\] or            \[E={{(900)}^{4}}\]


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