A) \[X{{=}_{2}}H{{e}^{4}},Y={{2}_{0}}{{n}^{1}}\]
B) \[X=2e,Y=a\]
C) \[X=a,Y=2e\]
D) \[X={{2}_{0}}{{n}^{1}},Y=2{{a}^{4}}\]
Correct Answer: A
Solution :
\[_{95}A{{m}^{241}}+X{{\xrightarrow[{}]{{}}}_{97}}B{{k}^{243}}+Y\] The value of X and Y \[_{95}A{{m}^{241}}{{+}_{2}}H{{e}^{4}}{{\xrightarrow[{}]{{}}}_{97}}B{{k}^{243}}+{{2}_{0}}{{n}^{1}}\] Hence,\[X{{=}_{2}}H{{e}^{4}}\]and \[Y={{2}_{0}}{{n}^{1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
