A) 0.71 A
B) 1.42 A
C) 0.375 A
D) 0.91 A
Correct Answer: A
Solution :
Potential energy of a particle is given by \[P.E.=\frac{1}{2}K{{x}^{2}}\] The kinetic energy is \[=\frac{1}{2}K({{A}^{2}}-{{x}^{2}})\] Now from equation K.E. and P.E. we obtain \[\frac{1}{2}K{{x}^{2}}=\frac{1}{2}K({{A}^{2}}-{{x}^{2}})\] \[{{x}^{2}}={{A}^{2}}-{{x}^{2}}\] \[2{{x}^{2}}={{A}^{2}}\] Or \[{{x}^{2}}=\frac{{{A}^{2}}}{2}\] Or \[x=\frac{A}{\sqrt{2}}=0.71A\]
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