Uttarakhand PMT Uttarakhand PMT Solved Paper-2006

  • question_answer
    A cone filled with water is revolved in a vertical circle of radius 4 m and the water does not fall down. What must be the maximum period of revolution?

    A)  2 s

    B)  4 s

    C)  1s

    D)  6 s

    Correct Answer: B

    Solution :

     When a cone filled with water is revolved in a vertical circle, then the velocity at the highest point is given by \[v=\,\ge \sqrt{gr}\] Also       \[v=r\omega =r\frac{2\pi }{T}\] Hence, \[T\le \frac{2r\pi }{\sqrt{rg}}=2\pi \sqrt{\frac{r}{g}}\] \[=2\pi \sqrt{\frac{4}{9.8}}\] \[=2\times 3.14\times 0.6389\] \[=4.0s\] So, \[{{T}_{\max }}=4\,s\]


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