A) \[\frac{13{{\mu }_{0}}l}{6a}\]
B) \[\frac{{{\mu }_{0}}l}{6a}\]
C) \[\frac{{{\mu }_{0}}l}{a}\]
D) none of these
Correct Answer: A
Solution :
\[B={{B}_{1}}+{{B}_{2}}+{{B}_{3}}\] \[=\frac{{{\mu }_{0}}(3I)}{2a}+\frac{{{\mu }_{0}}(2I)}{2(2a)}+\frac{{{\mu }_{0}}I}{2(3a)}\] \[=\frac{3{{\mu }_{0}}I}{2a}+\frac{{{\mu }_{0}}I}{2a}+\frac{{{\mu }_{0}}I}{6a}\] \[=\frac{9{{\mu }_{0}}I+3{{\mu }_{0}}I+{{\mu }_{0}}I}{6a}=\frac{13{{\mu }_{0}}I}{6a}\]You need to login to perform this action.
You will be redirected in
3 sec