A) \[\sqrt{2gr}\]
B) \[\sqrt{mgr}\]
C) 2mgr
D) \[gr\]
Correct Answer: A
Solution :
From the condition \[mgr=\frac{1}{2}m{{v}^{2}}\] \[\Rightarrow \] \[2gr={{v}^{2}}\] \[\Rightarrow \] \[v=\sqrt{2gr}\]You need to login to perform this action.
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