A) \[E=E{}^\circ +\frac{2.303RT}{nF}\log \frac{[M]}{[{{M}^{n+}}]}\]
B) \[E=E{}^\circ +\frac{2.303RT}{nF}\log \frac{[{{M}^{n+}}]}{[M]}\]
C) \[E=E{}^\circ -\frac{2.303F}{nRT}\log \frac{[{{M}^{n+}}]}{[M]}\]
D) \[E=E{}^\circ -\frac{2.303RT}{nF}\log [{{M}^{n+}}]\]
Correct Answer: B
Solution :
For \[{{M}^{n+}}+n{{e}^{-}}\xrightarrow[{}]{{}}M,\] \[E=E{}^\circ -\frac{2.303RT}{nF}\log \frac{M}{[{{M}^{n+}}]}\] \[=E{}^\circ +\frac{2.303RT}{nF}\log \frac{[{{M}^{n+}}]}{[M]}\]
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