A) 1: 2
B) 1: 4
C) 2:1
D) 4 : 1
Correct Answer: A
Solution :
Excess pressure inside the bubble, \[p=\frac{4T}{r}\] Then, \[{{p}_{1}}=\frac{4T}{{{r}_{1}}}\] ... (i) \[{{p}_{2}}=\frac{4T}{{{r}_{2}}}\] ...(ii) From Eqs. (i) and (ii), we have \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{4T/{{r}_{1}}}{4T/{{r}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\] \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{1}{2}\]
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