A) 20
B) 80
C) 120
D) 160
Correct Answer: C
Solution :
Input power\[=VI=200\times 10\] \[=2000\text{ }W\] Output power\[=\frac{40}{100}\times 2000\] \[=800\text{ }W\] Power loss in heating the armature \[=2000-800\] \[=1200W\] \[\therefore \] \[{{I}^{2}}R=1200\] Or \[R=\frac{1200}{{{I}^{2}}}\] \[=\frac{1200}{10\times 10}\] Or \[R=12\,\Omega \]You need to login to perform this action.
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