A) R
B) R/2
C) R/4
D) None of these
Correct Answer: A
Solution :
The resistance of two arms on the opposite corners of a square\[=R+R=2R\]. Therefore, for equivalent resistance between two opposite comers of a square, we have two resistance each of value 2R in parallel. So, \[\frac{1}{R}=\frac{1}{2R}+\frac{1}{2R}\] \[\frac{1}{R}=\frac{1+1}{2R}=\frac{2}{2R}\] \[R=R\]You need to login to perform this action.
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